Actuarial modeling is helpful to value a car manufacturer's
warrant liabilities, on newly developed batteries. Recently we have seen a case where Tesla Motors' earnings
were driven off both the level and accounting treatment of battery warrant
liabilities.
There are two basic significant considerations for this sort
of mathematical analysis. The
first is the battery "mortality" model to be used, and the second is
the survival probability relationships against both the vehicle age and the
mileage limits. For the first
consideration, popular frameworks have too large of an initial mortality to be
applied in practice here. These
models include the exponential, uniform, and Makeham type models. A customized and more rigorous
mortality function, grounded initially at zero and increasing at a 4% annual
rate fits the parameters of this problem.
For the second consideration, we must model an in-between,
positive relationship between a vehicle’s age and its mileage. In the current case of one of the
popular Tesla models, insurance payment is dependent upon the new battery's
failure prior to 6 years and prior to 125,000 miles. A small number of vehicles for example would have a battery
failure at 6 years and with less than 20,000 miles. Or a small number would fail in the first year and with
125,000 miles. But a more
substantial case would see some directional relationship between these survival
probabilities against the two variables here. In this note we will model a 50% co-relationship.
We begin our model proof with the whole annuity coverage
cost designed to be:
Here we will use a net δ of 10%, to incorporate both the
underlying interest rate and the future price discount rate on the replacement
value of the battery. The central
exponent to the first integral above is the survival probability, which we take
to the ¾ power to incorporate the joint survival probability on both age and
mileage. The erfc(x) function is
the error function noted by:
If one wants another approach to erfc(x) versus the integral above, they can use the incomplete gamma function of half and x^2, and divided by the square root of π. Moving on, this comes to a whole annuity of 8.5*0.6=5.2. The whole coverage would therefore be
1-δ*(whole annuity). Or
1-0.1(5.2)=0.45. In English, this
value shows that the automotive company would be able to offer a warrant
liability for 0.45 per dollar of current replacement value.
In Tesla’s case, we have a warrant liability for a limited
period of the first failure, prior to either 6-years or 125,000 miles. So we must take our closed form
definite integral and calculate it using numerical methods to be a fraction of
0.45, or in this case with Tesla’s limitations it is 0.26.
So the average warrant liability of 0.26 per dollar of
replacement value has a standard deviation of 0.2. To get there, we see that the variance of the coverage
estimate is computed using the following formula:
The Coverage@2δ is equal to 1-2δ*(term-annuity@2δ). And the standard deviation of the sample average would be equal to the square root of this variance divided by the square root of the sample size, or in Tesla’s case we have 10,000 vehicles. Again this comes to 0.2 per dollar of replacement value.
As a final estimation we show that the 90% confidence
interval (i.e., +1.65 standard deviations) for the warrant liability
valuation, given these term limitations, would be $20 million to $30
million. And note for the case of
Tesla, there is an approximately $21 million cumulative provisions. A company can actuarially sit at the
low end of the valuation estimate if they are assuming (right or wrong) that
future replacement costs are driven down at a substantially faster rate. Else we see a downward bias on future
earnings to compensate for the provisions estimates now.



No comments:
Post a Comment